Question

1) √3sin60° - √2cos45°
2) sin(180° - x) stiind ca sin x = 4/5
cos(180° - x) stiind ca cos x = 2/3

Multumesc !

Answer 1

$1) \sqrt3\dfrac{\sqrt3}{2} -\sqrt2\dfrac{\sqrt2}{2} =\dfrac{3}{2} -\dfrac{2}{2} = \dfrac{1}{2}$

2) $sin(180^0-x) = sin x = \dfrac{4}{5}$

  3)  $\cos (180^0-x) = -\cos x = - \dfrac{2}{3}$