Question

1/45+1,2(x)=0,(2)×x-0,0(4).
Aflati x.

Answer 1

[tex]\frac1{45}x+1.2x=0.(2)x-0.0(4) [/tex]

$\frac1{45}x+\frac{12}{10}x=\frac29x-\frac4{90}$

Se aduce la acelasi numitor(90):

[tex]2x+108x=20x-4 110x=20x-4 90x=-4 [/tex]⇒$x=-\frac4{90}=-0.0(4)$