Question

1+6+6la2+6la3+.....+6la2013

Answer 1

22,2,,3,3,3,3,1,1,1,4,,3,55,2,,434,34,534,5,435,3,53,35,4,34,5

Answer 2

prima varianta 6^0+6^1+6^2+6^3+...+6^2013=
[a^(n+1)-1]/a-1 unde
a^n=6^2013
[6^(2013+1)-1]/6-1=(6^2014-1)/5
sper ca am ajutat
a doua varianta S=6^0+6^1+6^2+6^3+...+6^2013
amplificam cu 6
6S=6^1+6^2+6^3+6^4+..+6^2014
scadem din a doua pe prima si rezulta:
6S-S=6^2014-6^0
5S=6^2014-1 sper ca s-a inteles