Question

1 820 + [(112 x 3- 36): n + 25] : 10 + 120 :5 = 1 849 ​

Answer 1

$1 \ 820 +[(112\cdot 3-36):n+25]:10+120:5=1 \ 849 \\ 1\ 820+[(336-36):n+25]:10+24=1 \ 849 \\ 1 \ 820 +(300:n+25):10+24=1 \ 849 \\ 1 \ 844+(300:n+25):10=1 \ 849 \\ (300:n+25):10=1 \ 849-1 \ 844=5 \\ 300:n+25=5 \cdot 10=50 \\ 300:n=50-25=25 \\ n=300:25 \\ \Rightarrow \boxed{n=12}}$

Answer 2

Răspuns:

$\frac{3693+60n}{2}$

Explicație pas cu pas:

1820+[(336-36)n+25]:10+24=

=1820+(300n+25):10+24=

=1820+$\frac{300n+25}{10}$+24=

=1844+$\frac{5(60n+5)}{10}$=

=1844+$\frac{60n+5}{2}$=

=$\frac{3688+60n+5}{2}$=

=$\frac{3693+60n}{2}$

sper ca am fost de ajutor