Question

1) a.(2 la puterea2-3) la puterea 100+5 impartit[3 la puterea 2+4x(e la putera 1-3 la putera0 )] x1 la putera 2013.

Answer 1

[tex]( 2^{2}-3)^{100}+5:[ 3^{2} +4x(e^{1}-3^{0} )] x 1^{2013} =0+5:[9+4x(1-0)]x1= [/tex][tex]0+5:(9+4)x1 = = 0+5:13x1= = 0.3 [/tex]