Question

1) a) 2x^2=1-(-1)^2013
2) a) 6x (5x+3)=18x
b) (x+2)^2+(x-2)^2=80
c)3x^2-4=4-3x^2

Answer 1

1)a)[tex] 2x^{2} =1-(-1)^{2013} [/tex]
$2 x^{2} =2$
$\frac{ 2x^{2} }{2} = \frac{2}{2}$
x=±√1x=1 or x=−1
2)a)6x(5x+3)=18x
$30x^{2} +18x=18x$
$30 x^{2} +18x-18x=18x-18x$
$30x^{2} =0$
$\frac{30 x^{2} }{30} = \frac{0}{30}$
$x^{2} =0$
x=±√0x=0
b)(x+2)²+(x−2)²=80
2x²+8=80
2x²+8−8=80−8
2x²=72
$\frac{ 2x^{2} }{2} = \frac{72}{2}$
x²=36
x=±√36x=6 or x=−6
c)3x²−4=4−3x²
3x²−4=−3x²+4
3x²−4+3x²=−3x²+4+3x²
6x²−4=46x²−4+4=4+46x²=8
$\frac{ 6x^{2} }{6} = \frac{8}{6}$
$x^{2} = \frac{4}{3}$
x=±$\sqrt{ \frac{4}{3} }$
x=1.154701,−1.154701