Question

1.a) 3√10₋(4√10₊3)₊5√10
b)₋7(3√2₊√3)₊3(√8₊√12)
c)2(√20₋√6)₋5(√5₊3√6)
d)√3·(√5₊√2)₊2(3√15₋√96)
e)2√3·(3√5₋4√7)₊√84₋√60
f)₋3√20·(√5₊√3)₋6(√15₋5)
 
2.Aratati ca urmatoarele nr. sunt intregi:
a=√5·(4√2₋3√5)₋2(2√10₊3)
b=2√7·(3₋√3)₊2(4₊√21)₋6√7
c=√12·(√32₋√3)₋4(7₊2√6)
d=√48·(√8₋√3)₋2√2·(4√3₋√2)

Answer 1

2deoarece se includ in multimea z