1. a) 8x la puterea a 3-a - 16x la a doua - 24x + 40x la a 5-a .
b) 15xy la a 2-a +45x la a doua y
c) 3x(x+2)-6(x+2)
2. x la a 2-a - 81/64
(x+radical din 2 la a 2-a) - 32
x-2radical din 3 x + 3 - (y-radical din 3) la a 2-a
urgent pls
Răspunsuri la întrebare
Răspuns de
0
1
a) 8x³ - 16x² - 24x + 40x⁵ = 8x (x² - 2x - 3 + 5x⁴)
b) 15xy² +45x²y= 15xy(y+3x)
c)3x(x+2) - 6 (x+2) = (x+2)(3x-6) = 3(x+2)(x-2)
2
x² - 81/64 = x² -(9/8)² = (x-9/8)(x+9/8)
(x+√2)² - 32 = (x+√2)² - (4√2)² = (x+√2-4√2) (x+√2+4√2) =(x-3√2)(x+5√2)
(x-2√3x+3) - (y-√3)² = (x-√3)² - (y-√3)² = (x-√3-y+√3)(x-√3+y-√3)=
=(x-y) (x+y-2√3)
a) 8x³ - 16x² - 24x + 40x⁵ = 8x (x² - 2x - 3 + 5x⁴)
b) 15xy² +45x²y= 15xy(y+3x)
c)3x(x+2) - 6 (x+2) = (x+2)(3x-6) = 3(x+2)(x-2)
2
x² - 81/64 = x² -(9/8)² = (x-9/8)(x+9/8)
(x+√2)² - 32 = (x+√2)² - (4√2)² = (x+√2-4√2) (x+√2+4√2) =(x-3√2)(x+5√2)
(x-2√3x+3) - (y-√3)² = (x-√3)² - (y-√3)² = (x-√3-y+√3)(x-√3+y-√3)=
=(x-y) (x+y-2√3)
Alte întrebări interesante