Question

1) a-b=2 si b+c=6 sa se calculeze 3a+b+4c
2) aflati cel mai mic numar natural careimpartitla 93 da rest 51

Answer 1

1.
a-b=2
b+c=6
a-b+b+c=2+6
a+c=8
3a+b+4c=3(a+c)+b+c=3x8+6=24+6=30

2.
a:93=1 si rest 51
a=93+51=144