Question

1.a+b=36 a=b+2
2.a+b=28 a=6•b
3.a,b,c 3nr consecutive impare
a+b+c=21
5.a-b=48 a=9•b
Va rog repede

Answer 1

1. b+b+2=36
2b=34
b=17
a=b+2
a=19

2. 6b+b=28
7b=28
b=4
a=24

3. a+a+2+a+4=21
3a+6=21
3a=15
a=5
b=7
c=9

5. 9b-b=48
8b=48
b=6
a=54