Question

1.Afla nr x ,din egalitatea de mai jos.8+10 :(58 -56)=(8+10) :(58-56)+X....SI EX .2 Suma a trei nr .naturale consecutive este 27 . Care sunt nr?

Answer 1

1) 8 + 10 : ( 58 - 56) = ( 8 + 10) : ( 58 - 56) + x 
18 : 2 + x = 13
9 + x = 13 
x = 13- 9 
x = 4 

2) a + b + c = 27 
a I__I
b I__I1I
c I__I1I1I 
3p = 27 - 3 = 24
1p = 24 : 3 
1p = 8 
a = 8 x 1 = 8
b = 8 + 1 = 9
c = 8 + 2 = 10

Answer 2

1.8+10:(58-56)=(8+10):(58-56)+x
1.8+10:2=18:2+x
1.8+5=9+x
1.13=9+x
1.x=13-9
1.x=4




2.a+b+c=27
consecutive=una dupa alta.DECI:
a+a+1+a+2=27
3a+3+27
3a=27-3=24
a=24:3
a=8
b=8+1
b=9
c=8+2
c=10