Question

1. Afla numerele întregi x si y pentru care xy+x-6y=14
2. Cea mai mica dintre fracțiile 13/18,43/48,65/72 este
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Answer 1

[tex]1) x(y+1)-6y-6+6=14\\ x(y+1)-6(y+1)=8\\ (x-6)(y+1)=8\\ x-6\in\{-8,-4,-2,-1,1,2,4,8\}\\ x\in\{-2,2,4,5,7,8,10,14\}\\ y+1\in{\{-1,-2,-4,-8,8,4,2,1\}\\ y\in\{-2,-3,-5,-9,7,3,1,0\}\\ (-2,-2);(2,-3),(4,-5);(5,-9);(7,7);(8,3);(10,1);(14,0)\\ 2)\\ ^{8)}\frac{13}{18}=\frac{104}{144}\\ ^{3)}\frac{43}{48}=\frac{129}{144}\\ ^{2}\frac{65}{72}=\frac{130}{144}\\ \frac{13}{18}\ \textless \ \frac{43}{48}\ \textless \ \frac{65}{72} [/tex]