Question

1) Aflati ecuatia de ardere dintre O, Cl, I cu Al, Mg, Ca, Zn, H, Li, Ba, Cu;
2) Ce cntitate de Mg se gasesc in 340 g fosfat de Mg si cati moli si atomi sunt in total?

Answer 1

4Al + 3O2= 2Al2O3               2  Mg +O2=2MgO             2 Ca+O2=2CaO

2Al +3Cl2=2AlCl3                     Mg +Cl2=MgCl2               Ca +Cl2=CaCl2

2Al +3I2 =2AlI3                        Mg +I2=MgI2                     Ca +I2=CaI2


2Zn+O2=2ZnO                          2 H2+O2=2H2O             4 Li+O2=2Li2O

Zn +Cl2=ZnCl2                          H2+Cl2=2HCl                  2 Li+Cl2=2Li Cl

Zn +I2=ZnI2                              H2+I2=2HI                            2Li+I2=2Li I


2Ba +O2=2BaO                        2 Cu +O2= 2CuO

Ba+Cl2=BaCl2                             Cu +Cl2=CuCl2

Ba+I2= Ba I2                                  Cu + I2 =Cu  I2




g ,moli Mg                          M=3.24+2.31+8.16=262
340 g Mg3(PO4)2              262 g---------1mol Mg3(PO4)2

                                           262g Mg3(PO4)2-----------72 g Mg
                                           340 g----------------------------xg Mg
                                         x=340.72:262=93,43 g Mg

                                        1mol Mg---------24 g Mg
                                         y moli Mg---------93,43 gMg

                                           y=93,43:24=3,89 moli Mg
                                                                           23
                                   1mol Mg----------6,023 .10   atomi Mg
                                   3,89 moli Mg--------z
                                                             23
                                   z=3,89.6,023 .10     atomi Mg