Question

1)Aproximati prin lipsa ,apoi prin adaos ,cu o eroare mai mica de 0,1 numarul rational x=3,67.
2)Calculati : a) 2 supra 3 + 4 supra 5 ; b ) 1 supra 2 - 1supra 6 + 0,(6); c )(0,5)x 2 supra 3 ; d) 1 : (-0,5) ; e ) ( - 1 supra 2 ) ^2 si f ) 2 ^-2 x 4 .
3 ) Rezolvati in Q ecuatiile : x+2 = 1 supra 2 ; 2x-1 = = 0 ; x: (0,5 ) = 1 ; 3(2x+1)=1
4 ) Calculati media aritmetica a numerelor 2, -1 si 1 supra 2 . Multumesc anticipat :xd dau coroana Urgent va rog :XD :!_"*

Answer 1

1) prin adaos este 3,7 si prin lipsa 3,6
2) a) 2/3 + 4 / 5= 10/15+12/15=22/15
b)1/2 - 1/6+ 0,(6)= 9/18-3/18+6/9= 6/18+6/9=1/3+2/3=3/3=1
c)((0,5)*2)/3=1/3
d) aplificam prin 2 si avem 2/-1
e)1/4
 f)1/4*4=1
3)x+2=1/2 =>2x+4=1 =>2x= -3=> x= -3/2
2x-1=0=>2x=1=>x=1/2
x/ (0,5)=1 => x=0,5=5/10
3(2x+1)=1=> 6x+3=1 => 6x=-2 => x=-2/6=-1/3
4)(2+(-1)+1/2)/3= (1+1/2)/3= 3/2/3=1/2