Question

1:Aria unui patrat cu diagonala de $8 \sqrt 2$ cm este egala cu ...cm$^{2}$.
2: Aratati ca:
($\sqrt7 + \sqrt14) ^{2} + (7- \sqrt2) ^{2} = (6 \sqrt2) ^{2}$.


Ajutati-maa. Plss.
Dau funditaa. :**

Answer 1

[tex]1) d=l \sqrt{2} =8 \sqrt{2} =\ \textgreater \ l=8 \\ A= l^{2} = 8^{2} =64 \\ 2) ( \sqrt{7}+ \sqrt{14} )^{2} +( 7- \sqrt{2} )^{2}=7+14 \sqrt{2} +14+49-14 \sqrt{2} +2= \\ 21+51=72=(6\sqrt{2})^{2}[/tex]