Question

1.Calculati: 1 supra 3 + 2 supra 5 : 6=

(-1 supra 5)²-4²=

{[1,(5)²-[0,(5)]²} · 9 supra 19=

36 - 81 : (-4 supra 9)⁻²=

(2 supra 3)⁻³ + 5 supra 4 - 9 supra 2=

(6-2)⁻²= 4⁻¹-2⁻¹=

(6-8+4)⁻² + (4 supra 3)⁻¹=

2. Calculati: (27 supra 16 : 9 supra 2 - 3 supra 4+ 1 supra 2)⁻¹ : 4 supra 3=

(2 intregi 1 supra 3 · 1 intreg 2 supra 7 + 1 supra 4 - 3 supra 2)⁻² ; 8 supra 5=
(1 + 1 supra 3) · [1,(3) - 1,5 :3+ 7 supra 6]⁻³=

VA ROG AJUTATI-MA! E URGENT! DAU 50 DE PUNCTE+ COROANA

Answer 1

a) 1/3+2/5:6=1/3+2/5*1/6=1/3+1/15=6/15. b) (-1/5)^2-4^2=1/25-16=-399/25. c) {[1,(5)^2-[0,(5)]^2}*9/19=(2,25-0,5)^2*9/19=1,75^2*9/19=27,5625/19. d) (2/3)^3+5/4-9/2=8/27+5/4-9/2=32+135-486totul supra108=319/108. e)36-81:(-4/9)^2=36-81:16/81=36-81*81/16=6085/16. f) (6-8+4)^2+4/3=2^2+4/3=4+4/3=16/3. Exercitiul 2 a) 27/16:9/2-3/4+1/2)^1:4/3=27/16*2/9-3/4+1/2):4/3=(3/8-3/4+1/2)*3/4=(3-6+4totul supra8)*3/4.1/8*3/4=3/32. b). ...=(7/3+9/7+1/4-3/2)^2=49+27totul supra21-5/4)^2=76/21-5/4)^2=(304-105totul supra 84)^2=199/84)^2=