Question

1)calculati (3X2 la puterea2002 -2 la puterea 2005):4 la puterea 1001
2)aflati numarul natural xdin egalitatea 2 la puterea x +3 X2 la puterea x=256

Answer 1

$(3*2^{2002} - 2^{2005} ): 4^{1001} =$
$= (3*2^{2002} - 2^{2005} ): 2^{ 2^{1001} =$
$= (3*2^{2002} - 2^{2005} ): 2^{2002} =$
$=3*2^{2002}: 2^{2002} - 2^{2005} : 2^{2002} =$
=3-$2^{3} =$=3-8=-5