Question

1. Calculaţi:
a) 102• [(3^17+2•3^17)^2:27^11 + 45^0)]; exercitii cu puteri
Va rog,pana maine !!!!!​

Answer 1

102×(3^17+2×3^17)^2÷27^11+45^0)]

102×[(3^51)^2÷27^11+45^0)]

102×(3^102÷27^11+45^0)

102×(27^100÷27^11+45^0)

102×(27^89+45^0)

102×(27^89+1^89)

102×28^89