Question

1. Calculați: a) 2(3x-2) + 4(4-2x); b) 3(1-5x)-2(2x - 1); c)(x-2y)(2x+y); d) (x+3)(4x-1); e) (x-2)(2x+1)-(2x+3)(1-3x); f)x-x+x²-x²-x²:x²; g) (2x + 1)²-(1-2x)²; h) (x²-x+1)(x²+x+1); atori: i) j) (x+y+2)²; k) (x-2y+3)²; 1) (x - 5)(2x-3)-(x - 5)² m) (x-3)(x+3)(x+3)(2x-1 n) (x-2)(x+2)(x² + 4); o) (x - 1)(x + 1)(x² + 1)(x* + 1). (2x-3)²-2(x+3)²;
Va roggg ,dau coroana​

Answer 1

Răspuns:

Salut

Explicație pas cu pas:

a) 2(3x-2) + 4(4-2x) = 6x-4 + 16-8x = 10x-20

b) 3(1-5x)-2(2x - 1) = 3-15x-4x+2 = -17x+5

c) (x-2y)(2x+y) = x(2x+y) - 2y(2x+y) = 2x^2 + xy - 4xy - 2y^2 = 2x^2 - 3xy - 2y^2

d) (x+3)(4x-1) = 4x^2+x-3 = 4x^2+x-3

e) (x-2)(2x+1)-(2x+3)(1-3x) = 2x^2-2x-2-2x^2-6x+3 = -4x+1

f) x-x+x²-x²-x²:x² = -x²:x² = -1

g) (2x + 1)²-(1-2x)² = (2x + 1)²-(1²-2x+2x²) = (2x + 1)²-(1-2x+2x²) = (2x + 1)²-(1-2x+2x²) = 4x²+4x+1-1+4x-4x² = 4x

h) (x²-x+1)(x²+x+1) = x⁴-x³+x²+x³-x²+x-x²-x-1 = x⁴-2x²-x+1

i) (x+y+2)² = (x+y+2)(x+y+2) = x²+2xy+4x+2yx+4y+4 = x²+2xy+2yx+4x+4y+4 = x²+2xy+2yx+4(x+y+2)

j) (x-2y+3)² = (x-2y+3)(x-2y+3) = x²-4xy+4y²+6x-12y+9 = x²-4xy+4y²+6x-12y+9

k) (x-5)(2x-3)-(x-5)² = 2x²-5x-10x+15-x²+10x-25 = 2x²-15x+40

l) (x-3)(x+3)(x+3)(2x-1) = x²+3x-9x-9-3x-9-3x-9-3x-9-3x-9-3x-9-3x-9-3x-9 = x²-12x-27

m) (2x-3)²-2(x+3)² = 4x²-12x+9-2(x²+6x+9) = 4x²-12x+9-2x²-12x-18 = 2x²-24

n) (x-2)(x+2)(x² + 4) = x³+x²-4x-8x-8-4x-8-4x-8-4x-8-4x-8 = x³

Sper ca macar cateva sunt corecte si iti va fii de ajutor