Question

1.Calculati :a) (2 radical 3-3) (radical 3+1)
b) ( radical 27-4) ( 3 radical 3+4)
c) (radical 2+1) la puterea 2 + 2 radical 8
d) ( radical 5 -2) la puterea 2 +4 ( radical 5 -1)

Coroana ( VREAU REZOLVAREA :D )

Answer 1

Bună! ⭐

$a) (2\sqrt{3} -3)*(\sqrt{3} +1)=6+2\sqrt{3} -3\sqrt{3} -3=-\sqrt{3} +3$

$b) (\sqrt{27} -4)*(3\sqrt{3} +4)=(3\sqrt{3} -4)*(3\sqrt{3} +4)=(3\sqrt{3} )^{2} -4^{2} =27-16=11$

$c) (\sqrt{2} +1)^{2} +2\sqrt{8} =2+2\sqrt{2} +1+4\sqrt{2} =3+6\sqrt{2} =3(1+2\sqrt{2} )$

$d) (\sqrt{5} -2)^{2} +4*(\sqrt{5} -1)=5-4\sqrt{5} +4+4\sqrt{5} -4=5$