Question

1.Calculati:
a) [(3^2*5-3^3)*5-3^2*8]:3^2-2^1
b) 2+3^3:[2^4+5*(6^2-5^2)-2^2*11
c) [(3^2*5+2^3*6+7*2^0)^2:1000+6]:4^2
d) {[11^3-3^6+199*(5^2-23)]:5^3+2}:10

2.Care este ultima cifra a numarului 6^10+5^11?

Answer 1

Răspuns:

a) [(9*5-27)*5-9*8]:9-2

[(45-27)*5-72]:9-2

[18*5-72]:9-2

[90-72]:9-2

18:9-2

2-2=0

b)2+27:[16+5*(36-25)-4*11

2+27:[16+5*11-44]

2+27:(16+55-44)P.S am transformat parantezele din [] in ();revenim:

2+27:(71-44)

2+27:27

2+1=3

c)[(9*5+8*6+7*1)^2:1000+6]:16

[(45+48+7)^2:1000+6]:16

[100^2:1000+6]:16

[10000:1000+6]:16

[10+6]:16

16:16=1

d){[1331-729+199*(25-23)]:125+2}:10

{[602+199*2]:125+2}:10

{[602+398]:125+2}:10

transformam {} in()

(1000:125+2):10

(8+2):10

10:10=1

iar ex 2 nuj cum se face