Question

1. Calculați:

a) (5√2 - 3√2) x + (6√2 - 4√2) x - (7√2 - √2) x + 4√2x =

b) (5√2 - 3√2) x + (6√2 - 4√2) x - (7√2 - √2) x + 4√2x =

c) (2√20 + √80) xy - √45xy + √125xy + (√5 + √180) xy =

Answer 1

a) (5√2 - 3√2) x + (6√2 - 4√2) x - (7√2 - √2) x + 4√2x =
     2√2x+2√2-6√2x+4√2x=2√2

b)Este identic cu a) sau este editat gresit...

c) (2√20 + √80) xy - √45xy + √125xy + (√5 + √180) xy =
    (4√5+4√5)xy-9√5xy+5√5xy+(√5+4√5)xy=
     8√5xy-9√5xy+5√5xy+5√5xy=9√5xy