Question

1.Calculați:
a) (7/10+1/4+2^3/40)×(7/2-3/8)×(1-2/3)^2
b)
20^3×15^15/45^6×189^4/140^3÷2^6/5^6×3^3/2^4×7^3×10^5
VA ROG AJUTATI-MA URGENT!!!!!!!!!!!!!!!!

Answer 1

punctul a
(28/40+10/40+8/40)*(28/8-3/8)*(3/3-2/3)^2=
46/40*25/8*1/9=
1150/2880

Answer 2

a) (7/10 + 1/4 + 2^3/40) x (7/2 - 3/8) x (1-2/3)^2 = 
   = (7/10 + 1/4 + 8/40) x (28/8 - 3/8) x (3/3-2/3)^2 = 
   = (28/40 + 10/40 + 8/40) x 25/8 x 1/9 = 
   = 46/40 x 25/8 x1/9 = 
   = 23/20 x 25/8 x 1/9 = 
   = 23/4 x 5/2 x 1/9 = 
   = 23 x 5 / 4 x 2 x 9 = 
  = 115/72

b) 20^3 x 15^15 / 45^6 x 189^4/140^3 : 2^6/5^6 x 3^3/2^4 x 7^3 x 10^5 = 
   = (2^2x5)^3 x (3x5)^15 / (3^2x5)^6 x (3^3x7)^4/(2^2x5x7)^3 : 2^6/5^6 x 3^3/2^4 x 7^3 x (2x5)^5 = 2^6 x 5^6 x 3^15 x 5^15/(3^12 x 5^6) x 3^12 x 7^4/ (2^6x5^3x7^3) x 5^6/2^6 x 3^3/2^4 x 7^3 x 2^5 x 5^5 = 2^6 x 5^6 x 3^15 x 5^15 x 3^12 x 7^4 x 5^6 x 3^3 x 7^3 x 2^5 x 5^5 / (3^12 x 5^6 x 2^6 x 5^3 x 7^3 x 2^6 x 2^4) = 2^11 x 3^30 x 5^32 x 7^7/(2^16 x 3^12 x 5^9 x 7^3) = 3^18x5^23x7^4/2^5