Question

1.Calculati:
ESTE URRRGGGEEENNNTTT!!!!!!!!!!!!

Answer 1

$\frac{ \sqrt{2} }{3\sqrt{2} } + \frac{ \sqrt{3}}{2\sqrt{3} } + \frac{1}{6} = ( \frac{1}{3}) ^{(2} + (\frac{1}{2}) ^{(3} + \frac{1}{6} = \frac{2}{6} + \frac{3}{6} + \frac{1}{6} = \frac{6}{6} = 1$$( \sqrt \frac{2}{3} + \sqrt{ \frac{3}{2} } + \sqrt{ \frac{1}{6} )$  X 1 / √6

Answer 2

     
$(\;\sqrt{\frac{2}{3}} + \sqrt{ \frac{3}{2} }+ \sqrt{ \frac{1}{6}}\;):\sqrt{6}= \\ \\ =( \frac{ \sqrt{2}}{ \sqrt{3}} + \frac{ \sqrt{3}}{ \sqrt{2}}+ \frac{1}{ \sqrt{6}} ) \cdot \frac{1}{\sqrt{6}}= \\ \\ =( \frac{ \sqrt{2}\cdot \sqrt{2}}{ \sqrt{3}\cdot \sqrt{2}} + \frac{ \sqrt{3}\cdot \sqrt{3} }{ \sqrt{2}\cdot \sqrt{3}}+ \frac{1}{ \sqrt{6}} ) \cdot \frac{1}{\sqrt{6}}=$

$=( \frac{ 2}{ \sqrt{6}} + \frac{ 3 }{ \sqrt{6}}+ \frac{1}{ \sqrt{6}} ) \cdot \frac{1}{\sqrt{6}}= \\ \\ \frac{2+3+1}{\sqrt{6}} \cdot \frac{1}{\sqrt{6}}=\frac{6}{\sqrt{6}} \cdot \frac{1}{\sqrt{6}}=\frac{6 \cdot 1}{\sqrt{6} \cdot \sqrt{6}}= \frac{6}{6} = \boxed{1}$