Question

1) calculati, folosind proprietatea a^m:a^n=a^m-n:
D) 7^17:7^13-7^3+13^0=
E)(11+4)^22:15^20-15^0=
F)(42:4)^2*9^18:27^6=

Answer 1

[tex]7^{17}:7^{13}-7^3+13^0=7^{17-13}-7^3+1=7^4-7^3+1=2058+1=2059\\ (11+4)^{22}:15^{20}-15^0=15^{22}:15^{20}-1=15^{22-20}-1=15^{2}-1=224\\ (42:14)^2\cdot9^{18}:27^6=3^2\cdot(3^2)^{18}:(3^3)^6=3^2\cdot 3^{36}:3^{18}=\\ =3^{2+36-18}=3^{20} [/tex]
Observatie: Am modificat un pic enuntul la F) si cred ca am procedat corect.