Question

1)Calculati in doua moduri:
84·(26+318)=
96·(517-125)=
(148+39)·419=
(786-104)·317=
68·(47+38-25)=
(167-89+35)·52=

2)Efectuati folosind factorul comun:
53·61+53·39=
37·23+37·54=
115·63-115=
25·31-25·16-8·25=
79·137-79·37=
89·45-28·89=
47·18+27·47+31·47=
74·49+49·12-49·55=


3)Calculati,respectind ordinea efectuarii operatiilor:
592·18+2009=
22000-406·37=
82·406-24594=
408·87+37·850=

Answer 1

1)84·(26+318)=84×344=28896 sau 84×26+318×84=2184+26712=28896
96·(517-125)=96×392=37632 sau 96×517-96×125=37632
(148+39)·419=419×187=78353sau 419×39+148×419=78353
(786-104)·317=682×317=216,194sau 317×786-317×104=216194
68·(47+38-25)=68×60=4080 sau 68×47+38×68-25×68=4080
(167-89+35)·52=113×52=5876 sau 52×167-89×52+35×52=5876 

2)Efectuati folosind factorul comun:
53·61+53·39=53(61+39)=5300
37·23+37·54=37(23+54)=2849
115·63-115=115(63-1)=7130
25·31-25·16-8·25=25(31-16-8)=25×7=175
79·137-79·37=79(137-37)=79×100=7900
89·45-28·89=89(45-28)=89×20=1780
47·18+27·47+31·47=47(18+27+31)=76×47=3572
74·49+49·12-49·55=49(74+12-55)=49×31=1519
3)Calculati,respectind ordinea efectuarii operatiilor:
592·18+2009=10656+2009=12665
22000-406·37=22000-15022=6978
82·406-24594=33292-24594=8698
408·87+37·850=35496+31450=66946