Question

1.Calculati masa in grame , nr de moli si nr de atomi de heliu intr-un volum de 224 litri .


2.Ce volum ocupa 3 moli de Argon ?


3.Ce masa si cati atomi se gasesc in 3 moli de Argon ?


Prima problema nu are legatura cu celelate 2 .

Answer 1

1.γ(He)=V/Vm=224l/22.4l/mol=10 mol

m=M*γ(He)=4*10=40 g

Na=6.02*10²³

N=Na*γ=6.02*10²³*10=6.02*10²⁴ ATOMI

2. V=γ(Ar)*Vm=3 mol*22.4l/mol=67.2l

3. m=M*γ=40g/mol*3mol=120 g

N=Na*γ=6.02*10²³*3=18.06*10²³ATOMI