Question

1.Calculati, respectand ordinea efectuarii operatiilor: a)20+(1,6x4,5-2,3) b) 2+1,2x[3+54x(1,7x3-0,5x2)] c)14,3x100-5,6x10 d)0,15+(1,473x10-0,02x100)x2,5 2. Calculati produsul dintre suma si diferenta numerelor 206,13 si 107,2

Answer 1

a)
20+(1,6×4,5-2,3)=20+(7-2,3)=20+4,7=24,7

b)2+1,2×[3+54×(1,7×3-0,5×2)]=2+1,2×[3+54×(5,1-1)]=2+1,2×(3+54×4,1)=2+1,2+(3+221,4)=2+1,2×224,4=265,68+2=267,68

c)14,3×100-5,6×10=1430-56=1374

d)0,15+(1,473×10-0,02×100)×2,52=
0,15+(14,73-2)×2,52=0,15+12,73×2,52=
0,15+32,0796=32,2296

206,13-107,2=98,93

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