Question

1. Calculati,respectand ordinea efectuarii operatiilor:
c) [(0,41(6)- 0,125) : (0,3125)+ 0,58(3)] : (0,6)=
d) [(0,41(6)- 0,4(6)) : (0,4) - 0,8(3)] : 0,3541(6)]=

Answer 1

c) [(0,41(6)- 0,125) : (0,3125)+ 0,58(3)] : (0,6)=
0,41(6)=(416-41)/900=375/900=15/36=5/12
0,125=125/1000=1/8
0,3125=3125/10000=25/80=5/16
0,58(3)=(583-58)/900=525/900=21/36=7/12
6/10=3/5

=[(5/12- 1/8) : 5/16+ 7/12 ]: 3/5=
=[(20-6)/48 ×16/5 + 7/12 ]: 3/5=
=[14/48 ×16/5 + 7/12 ]: 3/5=
=(14/15+7/12) ×5/3=
=(56+35)/60×5/3=
=91/60×5/3=
=91/36

d)[(0,41(6)-0,4(6)):(-0,4)-0,8(3)]:0,3541(6) =
0,41(6)=(416-41)/900=375/900=15/36=5/12
0,4(6)=(46-4)/90=42/90=7/15
0,8(3)=(83-8)/90=75/90=5/6
0,3541(6)= (35416-3541)/90000=31875/90000=1275/3600=17/48

=[(5/12-7/15):(-0,4)-5/6)]:17/48 =
=[(25-28)/60):(-4/10)-5/6)]:17/48 =
=[(-3)/60):(-2/5)-5/6)]:17/48 =
=[-1/20)*(-5/2)-5/6)]:17/48 =
=[1/8-5/6)]:17/48 =
=[(6-40)/48] x48/17 =
=-34/48 x48/17
=-2