Question

1. Calculează 3 x a-b: 3+3 xc, știind că: a=(4+5:5-3): 2; b=11-6: [5-4: (7-5:1)]; c=[(8+8): 4-3] x (9-3 x 3).



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Answer 1

Explicație pas cu pas:

$a = (4 + 5 \div 5 - 3) \div 2 = (4 + 1 - 3) \div 2 = (5 - 3) \div 2 = 2 \div 2 = 1$

=> a = 1

$b = 11 - 6 \div [5 - 4 \div (7 - 5 \div 1)] = 11 - 6 \div [5 - 4 \div (7 - 5)] = 11 - 6 \div (5 - 4 \div 2) = 11 - 6 \div (5 - 2) = 11 - 6 \div 3 = 11 - 2 = 9$

=> b = 9

$c = [(8 + 8) \div 4 - 3] \times (9 - 3 \times 3) = (16 \div 4 - 3) \times (9 - 9) = (4 - 3) \times 0 = 1 \times 0 = 0$

=> c = 0

$3 \times a - b \div 3 + 3 \times c = 3 \times 1 - 9 \div 3 + 3 \times 0 = 3 - 3 + 0 = 0 + 0 = 0$