Question

1.Calculeaza:

a) (1+3*3^2*3^4):(3^7+1)=

b) (6^2+2^2-2^0):13*3^7:3^6+3^2=

c) (4+2^192:2^188):5=

d)5^19*5^21:(3*11-168:6)^38=

e) 2^2+2^4:2-0^77-1^5=

f)2*[2+3*(2^3:2+3*3^2-5^2)]=

g)(3^0*3*3^5:3^5+3^3):15=

Answer 1

Răspuns:

a) (1+3×3²×3⁴):(3⁷+1)=

(1+3⁷):(3⁷+1) Ambele paranteze sunt la fel deci rezultatul este 1.

b) (6²+2²-2⁰):13×3⁷:3⁶+3²

=(36+4-1):13×3¹+3²

=39:13×3+9

=3×3+9

=9+9

=18

c)(4+2¹⁹²:2¹⁸⁸):5

=(4+2⁴):5

=(4+16):5

=20:5

=4

d)5¹⁹×5²¹:(3×11-168:6)³⁸

=5¹⁹×5²¹:(33-28)³⁸

=5¹⁹×5²¹:5³⁸

=5⁴⁰:5³⁸

=5²

=25

e)2²+2⁴:2-0⁷-1⁵

=4+16:2-0-1

=4+8-0-1

=12-1

=11

f)2×[2+3×(2³:2+3×3²-5²)]

=2×[2+3×(2²+3³-5²)]

=2×[2+3×(4+27-25)]

=2×(2+3×6)

=2×20

=40

la g nu stiu dar sper ca restul sunt corecte!

O zi buna!