Question

1. Calculeaza radical din 17 la puterea 2 + 2*17*19+19 la puterea 2
2. Calculeaza 4 supra radical din 3 * radical din 2 supra 2 * 2014 la puterea 0 supra radical din 6
3. Calculeaza, precizand formula: (-3x-4) la puterea 2. Formula aplicata este : ...
4. Fie A={-2; radical din 2; 2 supra 3; 1 supra radical din 6; -5 supra 6; -radical din 9 supra 3; A intersectat (multimea R - multimea Q) = ...

Answer 1

$\displaystyle 1). \sqrt{17^2+2 \cdot 17 \cdot 19 +19^2} = \sqrt{289+646+361} = \sqrt{1296} =36 \\ \\ 2). \frac{4}{ \sqrt{3} } \cdot \frac{ \sqrt{2} }{2} \cdot \frac{2014^0}{ \sqrt{6} } = \frac{4 \sqrt{2} }{2 \sqrt{3} } \cdot \frac{1}{ \sqrt{6} } = \frac{4 \sqrt{2} }{2 \sqrt{18} } = \frac{4 \sqrt{2} }{6 \sqrt{2} }= \frac{2}{3} \\ \\ 3).(-3x-4)^2=(3x+4)^2=(3x)^2+2 \cdot 3x \cdot 4+4^2=9x^2+24x+16 \\ \\ Formula : (a+b)^2$

$\displaystyle 4).A= \left \{ -2; \sqrt{2} ; \frac{2}{3} ; \frac{1}{ \sqrt{6} } ;- \frac{5}{6} ;- \frac{ \sqrt{9} }{3} \left \} {{} \atop {}} \right.$

$\displaystyle A ~\cap ~(R-Q)= \left \{ \sqrt{2} \left \} {{} \atop {}} \right.$