Question

1)Calulati ce volum ocupa in c.n:a)1g N₂; b) 1g NH₃; c)24.088*10²³ molecule N₂; d)24.0888*10²⁶ molecule NH₃.


2)Calculati masa a: a) 67.2 dm³(c.n.)N₂; b)67.2 dm³ (c.n.)NH₃.


3)Calculati numarul de moli din:a)56g N₂; 34gNH₃ b)4.48 dm³ (c.n.) N₂; 4.48L(c.n.)NH₃; c)9.033*10²³ molecule N₂; 9.033*10²⁶ molecule NH₃.

URGENT ESTE PENTRU MAINE DAU COROANA SI ROG SERIOZITATE

Answer 1

1.a) 1g..x l
     28g..22,4l; x=0.8l
b)1g ...xl
  17g...22,4 ;x=1.31l
c)24.088*10^23....x l
   6.022*10^23 ... 22,4l ;x= 89.6l 
d)24.088*10^26 ...xl
   6.022*10^23 ..22,4l; x= 89.6*10^3 l 
2. a) 67,2l... x
       22.4l....28 ; x=84g
b)67,2l ...xg
   22.4l....17g ; x=51g
3.a)56/28=2moli ; 34/17=2moli 
b)4,48/22,4=0,2 moli ;4,48/22,4=0,2 moli
c)9,033*10^23/6.033*10^23=1,49 moli ; 9,033*10^26/6,033*10^23=1,49*10^3 moli