Question

1.Cantitatea de oxid de cupru care reactioneaza cu o solutie de acid clorhidric si care formeaza 27 sare(g-moli)
2.Masa de azot necesara obtinerii prin sinteza a 3 moli de amoniac(moli)

Answer 1

1. CuO + 2HCl -> CuCl2 + H2O

MCuCl2=ACu+2ACl=64+71=135g/mol

n=m/M=27/135=0,2 moli CuCl2 (sare)

Nr de moli sare corespunde nr-lui de moli de CuO => nCuO=0,2 moli

MCuO=ACu+AO=64+16=80g/mol

n=m/M=>m=n*M=80*0,2=16g CuO

2. N2 + 3H2 -> 2NH3

MN2=2AN=2*14=28g/mol


28g N2.......................2 moli NH3
xg N2.........................3 moli NH3

x=28*3/2= Calculeaza !!