Question

1)Cati protoni exista in 710 g Cl2)
2)Cati protoni exista un 2160 kg Ag?
urgent​

Answer 1

Răspuns:

Explicație:

1.

-se afla nr. de moli de Cl2 din 710g Cl2

MCl2=2.35,5 =71-------> 71g/moli

n= 710g : 71g/moli=10moli Cl2

ZCl=17  -------> 17 p , 17 e

1mol Cl2---------2 . 6,023.10²³atomi Cl------------2 . 17 . 6,023. 10²³  p

10 moli Cl2--------------------------------------------------x p

x=10 . 2 .17 . 6,023.10²³ p = 2047,82 .10²³ p

2.

2160kg=2160000g

ZAg =47---------> 47 p ,47 e

A=108

n=2160000g: 108g/moli=20000moli Ag

1molAg ----------6,023.10²³atomi Ag---------47 . 6,023.10²³ p

20000moli--------------------------------------------------x p

x= 20000 . 47 .6,023.10²³ p = 5661620.10²³ p