Question

1.Ce cantitate de hidrogen se consuma pentru a obtine 4 moli HCl ?
2.Sa se determine masa de fier de puritate 75% necesara pentru a obtine 11,6 g Fe2O3

Answer 1

H2 + Cl2 => 2 HCl
2 g H2...........2 moli HCl
x g H2..............4 moli HCl
x = 8 g H2

4 Fe + 3 O2 => 2 Fe2O3
4*56 g Fe............2*160 g Fe2O3
x g Fe..................11,6 g Fe2O3
x = 8.12 g Fe
puritatea = m pura/m impura * 100
m impura = m pura/puritate * 100
m impura = 8.12/75 * 100 = 10.8266 g Fe

Answer 2

1. H₂ + Cl₂ = 2HCl

1mol H₂....................2 moli HCl
x................................4moli HCl
x=4/2
x=2 moli H₂

2. MFe₂O₃=2AFe+3AO=2*56+3*16=160g/mol

n=m/M=11,6/160=0,0725 moli Fe₂O₃

4Fe + 3O₂ = 2Fe₂O₃

4*56g Fe.................2 moli Fe₂O₃
x=.............................0,0725 moli Fe₂O₃

x=0,0725*4*56/2
x=8,12g Fe pur

puritatea = masa pura/masa impura*100 => masa impura = masa pura *100/ puritate = 8,12*100/75 = 10,82666g Fe