Question

1) Ce volum de acetilena masurat in conditii normale se obtine din 3200 kg metan la un randament al reactiei de 90% ?

2) Din ce cantitate de metan (g) se obtine 100g de clorometan la un randament de 75% ?

Answer 1

1) 2CH₄ ⇒ C₂H₂ + 3H₂

2*16kg CH₄....................26kg C₂H₂
3200kg CH₄...................x = 2600 kg C₂H₂

practic: 2600*90/100 = 2340 kg C₂H₂

 n = V/Vm  =  m/M  => V  = Vm*m/M = 22,4*2340/26 = 2016m³ C₂H₂

2) CH₄ + Cl₂ ⇒CH₃Cl + HCl

16g CH₄...........50,5g CH₃Cl
xg CH₄.............100g CH₃Cl

x = 31,68g CH₄

practic: 31,68*75/100 = 23,76g CH₄