Question

1.) Claculati : 4√10-2√8-(6+4√10)=
2(4+√21)-6√7+2√7×(3-√3)=
4√3(√8-√3)-2√2×(3√3-√2)=
2)....... {4√2+4×[3√3+3×(3√2-√3)]}:10-√2=
3√5-7×{√2+[20√5-2×(√5-9√2):18]}=
√63×[7√27-3×(7√3+√28)]+16=
30√180+4√5×{18√2-3√5×[2√40-3(√40-√5)]}=
3) Scoateti factorii de sub radical :
a) (√18+√288)-(√98+√200)=
b) 4√8+5√108-2√72=
c)3√162-5√12-4√75+2√50=
d) -4√216+3√96-√54+2√600
4..)Restrangeti , dupa ce ati scos factorii de sub radicali:
a) √18+√8-√32
b) √45+√125+√20
c) √3+√27-√12+√48
d) √24-√54-6√6
DAU COROANA URGENT....

Answer 1

1) 4√10-2√8-(6+4√10)=
=4√10-4√2-6-4√10=
=-4√2-6=
=2(2√2-3)
 
2(4+√21)-6√7+2√7×(3-√3)=
=8+2√21-6√7+6√7-6√21=
=8-4√21=
=4(2-√21

4√3(√8-√3)-2√2×(3√3-√2)=
=4√3(2√2-√3)-6√6+8=
=8√6-12-6√6+8=
=2√6-4=
=2(√6-2)=

2) {4√2+4×[3√3+3×(3√2-√3)]}:10-√2=
={4√2+4×[3√3+9√2-3√3)]}:10-√2=
=(4√2+4×9√2):10-√2=
=(4√2+36√2):10-√2=
=40√2:10-√2=
=4√2-√2=
=3√2

 3√5-7×{√2+[20√5-2×(√5-9√2):18]}=
=3√5-7×[√2+(20√5-2√5-18√2):18]=
=3√5-7×[√2+(18√5-18√2):18]=
=3√5-7×(√2+√5-√2)=
=3√5-7√5=
=-4√5

√63×[7√27-3×(7√3+√28)]+16=
=3√7×[21√3-3×(7√3+2√7)]+16=
=3√7×(21√3-21√3+6√7)+16=
=3√7×6√7+16=
=18×7+16=142

 30√180+4√5×{18√2-3√5×[2√40-3(√40-√5)]}=
=180√5+4√5×{18√2-3√5×[4√10-3(2√10-√5)]}=
=180√5+4√5×{18√2-3√5×[4√10-6√10+√5)]}=
=180√5+4√5×[18√2-3√5×(-2√10+√5)]=
=180√5+4√5×(18√2+6√50-15)=
=180√5+4√5×(18√2+30√2-15)=
=180√5+4√5×(48√2-15)=
=180√5+192√10-60√5=
=120√5+192√10=
=24√5(5+8√2)


3) Scoateti factorii de sub radical :
a) (√18+√288)-(√98+√200)=
=(3√2+12√2)-(7√2+10√2)=
=15√2-17√2=
=-2√2

b) 4√8+5√108-2√72=
=8√2+30√3-12√2=
=30√3-4√2=

c) 3√162-5√12-4√75+2√50=
=27√2-10√3-20√3+10√2=
=37√2-30√3=

d) -4√216+3√96-√54+2√600=
=-24√6+12√6-3√6+20√6=
=-24√6+12√6-3√6+20√6=
=5√6

4..)Restrangeti , dupa ce ati scos factorii de sub radicali:
a) √18+√8-√32=
=3√2+2√2-4√2=
=√2

b) √45+√125+√20=
=3√5+5√5+2√5=
=10√5


c) √3+√27-√12+√48=
=√3+3√3-2√3+4√3=
=6√3

d) √24-√54-6√6=
=2√6-3√6-6√6=
=-7√6