Question

1. claculati:
a) (-3x²)³ : (3x)²
b) (2x+3) (x-1)

Answer 1

a) $[tex](-3 x^{2} ) ^{3} : (3x)^{2} = -27 x^{6} : 9 x^{2} = -3 x^{3}$
b)$(2x+3)(x-1)= 2 x^{2} - 2x + 3x - 3 = 2 x^{2} +x-3$

Answer 2

a)(-3x²)³:(3x)²=(-3)³·(x²)³:3²·x²(adica fiecare element se ridica la puterea indicata)
= -27x⁶:9x²=-3x⁴
b)(2x+3)(x-1)=2x·x-2x·1+3·x-3·1=2x²-2x+3x-3=2x²+x-3
sper ca te-am ajutat