Question

1.Cum pot sa aflu sin A,daca triunghiul ABC are aria egala cu 15,iar AB=6 si AC=10?

Answer 1

$S _{ABC} = \frac{AB*AC*sinA}{2} \\ 15= \frac{6*10*sinA}{2} \\ 30=60sinA \\ 60sinA=30 \\ sinA= \frac{30}{60} \\ sinA= \frac{1}{2}$