Question

1.demostrati ca numarul a=2 la puterea n+2 *3 la puterea n+2+5*6 la puterea n+2 la puterea n+1 este divizibilcu 47,oricare ar fi n apartine N.

2.daca a+b=25 si b+c=35,calculati 3a+6b+3c

Answer 1

2. 3a + 6b+3c = 3a+3b+3b+3c = 3(a+b)+3 (b+c)=3*25+3*35=75+105=180