Question

1.Descompuneti in factori
2x+1 in paranteza²=
3a+5 in paranteza²=
2x+3y in paranteza²-x+y in paranteza²=

2.Calculati rapid folosind formule de calcul prescurtat
98²-2²=
994²-6²=
93.107=100-7 pe langa 100+7=
192.208=
Descompuneti in factori ,grupand mai intai convenabil termeni
3x+3y+ax+ay=
7a+ab-7x+bx=
2x+2y+abx+aby=
5x³+15x²+4x+12=

va rog!!!

Answer 1

(2x+1)²=4x²+4x+1
(3a+5)²=9a²+30a+25
(2x+3y)²-(x+y)²=
=(2x+3y-x-y)(2x+3y+x+y)=
=(x+2y)(3x+4y)=
=x²+10xy+8y²


2.Calculati rapid folosind formule de calcul prescurtat
98²-2²=(98+2)(98-2)=100*96=960
994²-6²=(994+6)(994-6)=1000*988=9880
 93 ×107=(100-7)(100+7)=10000-49=9951
192×208=(200-8)(200+8)=40000-64=39936

Descompuneti in factori ,grupand mai intai convenabil termeni
3x+3y+ax+ay=3(x+y)+a(x+y)=(x+y)(3+a)
7a+ab+7x+bx=7a+7x+ab+bx=7(a+x)+b(a+x)=(a+x)(7+b)
 2x+2y+abx+aby=2(x+y)+ab(x+y)=(x+y)(2+ab)
5x³+15x²+4x+12=5x²(x+3)+4(x+3)=(x+3)(5x²+4)