Question

1.descompuneti în factori:
a) 4x²-9=
b) 36x²-x⁴=
c) 16x²y²-1=
d) 25-4x²=
e) 64x²-49=
f) 81-9x⁴=
g) 121x²-144=
h) 49x²-100=
i) x⁶/4-1/25=
va rog, e urgent ​

Answer 1

Răspuns:

Explicație pas cu pas:

a)4x²-9=2²x²-3²=(2x)²-3²=(2x-3)(2x+3)

b)36x²-x⁴=x²(36-x²)=x²(6-x)(6+x)

c)16x²y²-1=(4xy-1)(4xy+1)=(2√xy-1)(2√xy+1)(4xy+1)

d)25-4x²=5²-2²x²=5²-(2x)²=(5-2x)(5+2x)

e)64x²-49=8²x²-7²=(8x)²-7²=(8x-7)(8x+7)

f)81-9x⁴=9(9-x⁴)=9(3-x²)(3+x²)

g)121x²-144=11²x²-12²=(11x)²-12²=(11x-12)(11x+12)

h)49x²-100=7²x²-10²=(7x)²-10²=(7x-10)(7x+10)

i)x⁶/4-1/25=1/100(25x⁶-4)=1/100(5x³-2)(5x³+2)

formula.folosita:a²-b²=(a-b)(a+b)