Question

1.Descompuneti in produs de puteri de factori primi numerele:
2500, 144000, 2520, 729, 625, 1800
ACUM DAU COROANA IN SPECIAL 625 PRIMUL VA ROG

Answer 1

Răspuns:

2500 = 2²·5⁴

144000 = 2⁷·3²·5³

2520 = 2³·3²·5·7

729 = 3⁶

625 = 5⁴

1800 = 2³·3²·5²

625 I 5

125 I 5

25 I 5

  5 I 5

Answer 2

Răspuns:

2500-2×2×5×5×5×5 sau

${2}^{2} \times {5}^{4}$

144000-

${2}^{7} \times {5}^{3} \times {3}^{2}$

2520-

${2}^{3} \times 9 \times 7 \times 5$

729-

${3}^{6}$

625-

${5}^{4}$

1800-

${2}^{3} \times {5}^{2} \times {3}^{2}$