Question

1)Determinati inversul numarului rational a=1,125*[1+0.(3)]

Answer 1

$a= 1,125 *(1+ \frac{3}{9} )=1,125 *\frac{3+1}{3}= \frac{1125}{1000} * \frac{4}{3} =\frac{375}{250}=\frac{3}{2}$

inversul numarului rational este: $\frac{2}{3}$