Question

1.Efectuati:
a)x√(1-√3)²+y√(2-√3)²-√3(x-2y)+2(x-y)
b)(x²+y²-13) la puterea 2004,daca x=√3+√2 si y=√6-1

Answer 1

a)x|1-√3|+y|2-√3|-√3x+2√3y+2x-2y=
√3>1
2>√3
x(√3-1)+y(2-√3)-√3x+2√3y+2x-2y=
√3x-x+2y-√3y-√3x+2√3y+2x-2y=
x+√3y
b)(√3+√2)^2=3+2√6+2=5+2√6.
(√6-1)^2=6-2√6+1=7-2√6
(x^2+y^2-13)^2004=
(5+2√6+7-2√6-13)^2004=
(12-13)^2004=
1