Question

1. Efectuați calculele:
a) (x + 2)² + (x+3)²-2(x-4)²;
b) (x+4)²-(2x-3)² + 3(x − 3)²;
d) (x-2)² + (2x + 3)² - 4(x-4)²;
c) 2(x+2)²-3(x-4)² + (2x − 5)²;
e) 2(x+4)²-3(x-5)²-(4-3x)(4+3x).

Answer 1

Răspuns:

Explicație pas cu pas:

1. Efectuați calculele:

a) (x + 2)² + (x+3)²-2(x-4)²=x²+4x+4+x²+6x+9-2(x²-8x+16)=

x²+4x+4+x²+6x+9-2x²+16x-32=26x-19    

b) (x+4)²-(2x-3)² + 3(x − 3)²=x²+8x+16-(4x²-12x+9)+3(x²-6x+9)=

x²+8x+16-4x²+12x-9+3x²-18x+27=2x+34    

d) (x-2)² + (2x + 3)² - 4(x-4)²=x²-4x+4+4x²+12x+9-4(x²-8x+16)=

x²-4x+4+4x²+12x+9-4x²+32x-64=x²+40x-51        

c) 2(x+2)²-3(x-4)² + (2x − 5)²=2(x²+4x+4)-3(x²-8x+16)+4x²-20x+25=

2x²+8x+8-3x²+24x-48+4x²-20x+25=3x²+12x-15      

e) 2(x+4)²-3(x-5)²-(4-3x)(4+3x)=2(x²+8x+16)-3(x²-10x+25)-(16-9x²)=

2x²+16x+32-3x²+30x-75-16+9x²=8x²+46x-59