Question

1)

Efectuați folosind formula (a-b)(a+b)=a²-b²:

a)

(3x-4)(3x+4)

b)

(5x-2)(5x+2)

2)

Efectuați folosind formula (a-b)(a+b)=a²-b²:

a)

(x-1/3)(x+1/3)

b)

(x-1/4)(x+1/4)

3)

Efectuați folosind formula (a-b)(a+b)=a²-b²:

a)

(√5x-3)(√5x+3)

b)

(√2x-√7)(√2x+√7)

4)

Efectuați folosind formula (a-b)(a+b)=a²-b²:

a)

(x-2)(x+2)(x²+4)

b)

(x-5)(x+5)(x²+25)

5)

Calculați folosind formula:(a-b)(a+b)=a²-b².

a)

(2-√3)(2+√3)-(√5-1)(√5+1)

b)

(2√5-1)(1+2√5)+(√13+7)(7-√13)

Trebuie cu rezolvare!!!

Answer 1

^ inseamna la puterea a 2
1.a) (3x)^2-4^2=9x^2-16
b) (5x)^2-2^2=25x^2-4

2a) x^2-(1/3)^2=x^2-1/9
b) x^2-(1/4)^2=x^2-1/16

3a) (√5x)^2-3^2=5x^2-9
b) (√2x)^2-7^2=2x^2-49

4a) (x^2-4)(x^2+4)=x^4-16
b) (x^2-25)(x^2+25)=x^4-625

5a) (2^2-√3^2)-(√5^2-1^2)=4-3-5+1= -3
b) (2√5)^2-1^2+√13^2-7^2=20-1+13-49= -17

Answer 2

••••••••••••••••••••••••••••••