Question

1.efectuati utilizând factorul comun :
a.3•45+3•15=
b.20•48+20•2=
c.28•521-28•21=
d.23•718-126•23=
e.15•38+15•162=
f.702•65+35•702=
g.2513•1001-2413=
h.2029•599+2928=
i.1289•337+1289•663=
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Answer 1

Răspuns:

3(45+15)=3 ×60=180

20(48+2)=20×50=1000

28(521-21)=28×500=1400

23(718-126)=23×592=13616

15(38+162)=15×200=3000

702(65+35)=702×100=70200

2413(1001×1)=2413×1001=2415413

2028(1×599)=2028×599=1214772

1289(337+663)=1289×1000=1289000