Question

1) hidrocarbura care are formula bruta CH2 si densitatea relativa a vaporilor sai in raport cu azotul, dN2=2 are formula moleculara ........

2) hidrocarbura saturata care are densitatea in raport cu hidrogenul, d=8 este ......

Answer 1

1) dN2 = M substanta/28 =) M substanta = 28× dN2 = 28 × 2 = 56 g/mol
(CH2)n
n= M polimer/M monomer
M monomer = 12+2=14
n=56/14=4 =) C4H8 (butena)

2)Hidrocarbura saturata = alcan
dH2 = M substanta /2 =) M substanta = 2× dH2 = 2×8 = 16 g/mol
Formula generala alcan: CnH2n+2
M CnH2n+2 = 14n +2 =)
14n +2 = 16 =) n=1 =) CH4 (metan)

Answer 2

1) dgaz=M/Mgaz==>M=d*Mgaz=2*28=56g/mol               MN2=28g/mol
 
(CH2)n=56==>14n=56==>n=4       C4H8      NE=1 ;  1-butena, 2-butena,etc

2) d=M/Mgaz==>M=d*Mgaz=8*2=16g/mol                    MH2=2g/mol

Fiind o hidrocarbura saturata formula generala este : CnH2n+2

CnH2n+2=16==>14n=14==>n=1    ; CH4 - metan